Solve each equation for x.a. x−10=0b. x/2+20=0c. Demanding Dwight insists that you give him two solutions to the following equation:(x−10)(x/2+20)=0Can you provide him with two solutions?

Answer:a) x = 10b) x = -40c) x = 10, -40Step-by-step explanation:a)[tex]x-10=0[/tex]Taking 10 to the right hand side 10 becomes positive[tex]\\\Rightarrow x=10[/tex]So x = 10b)[tex]\frac{x}{2}+20=0[/tex]Taking 20 to the right hand side 20 becomes negative[tex]\frac{x}{2}=-20[/tex]Multiplying both sides by 2[tex]x=-40[/tex]So, x = -40c)[tex](x-10)(\frac{x}{2}+20)=0\\\Rightarrow x-10=0, \frac{x}{2}+20=0\\\Rightarrow x=10, \frac{x}{2}=-20\\\Rightarrow x=10, x=-40[/tex]Hence, x = 10, -40So, two solutions can be provided